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You can multiply each side of the multiplicative inverse equation by the other inverse to show that any two multiplicative inverses are equal. Here it is more formally.

Theorem: For all x in R, there exists y in R s.t. x * y = 1. If there is a y' in R such that x * y' = 1, then y = y'.

Proof:

- Start with x * y = 1.

- y * x = 1 (commutative)

- (y * x) * y' = 1 * y' = y'

- y * (x * y') = y' (associative)

- y * 1 = y' (because x*y' = 1)

- y = y'

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Q: How do you prove the multiplicative inverse is unique?
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