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How do you solve. 1 number is 2 less than a second number if ya take half of the first and increase it by the second the result is at least 41. find the least poss. value for the second number?
Dedwards08
First number = x - 2
Second nubmer = x
First Increased by Second = x - 2 + x = 2x - 2
2x - 2 >= 41
2x >= 43
x >= 43/2 ( = 21.5 = 21 1/2)
The second number must be at least 43/2.
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