-5x2 + 5x + 60 = 0
Remove the common factor of 5
-x2 + x + 12 = 0
Where the coefficient of x2 is negative, it is best to make it positive by multiplying throughout by -1
x2 - x - 12 = 0
The above equation will factorise.
(x - 4)(x + 3) = 0 ; therefore x - 4 = 0 when x = 4, or x + 3 = 0 when x = -3
The solutions (roots) of this equation are x = 4 and x = -3.
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
The discriminant is 385.
If 5x plus 3y equals 13, the x equals 2 and y equals 1. This is because 5x2=10 and 3x1=3, and 10+3=13.
5x2 + 20x = 5x (x + 4)
5x2+7x = 12 5x2+7x-12 = 0 (5x+12)(x-1) = 0 x = -12/5 or x = 1
-5x2 = -75 x2 = 25 x = ±sqrt( 25 ) x = ±___
5x2=8x Divide with x on both sides5x= 8 Solve xx=8/5
5x2 + 9x + 4 = (x + 1)(5x + 4).
you cant
23
7
x = -8