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Q: How do you solve 1 over 5 plus 1 over 11 equals?

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a = 4

r + 11 + 8r = 29

9y subtract 11 equals 7

x = 5, y = -1

x=4 x=0

The answer is 21 because if 21 is divided by 3 it equals 7 plus 4 equals 11.

q = 78

r + 11 = 19 r + 11 - 11 = 19 - 11 r = 8

If: 7+t = 11 Then: t = 11-7 So: t = 4

You subtract 11 from both sides and r equals negative 7. See... r+11=3 -11 -11 r=7

6a + 5a = -11 Combining like terms: 11a = -11 Dividing by 11: a = -1

(0,7)

The answer is 11

v is -15... -15*2 = -30... -30+11= -19.

-2x+13y=11 13y=2x+11 y=2x/13 + 11/13

If 2x + 5 = 11, then 11 - 5 = 2x 6 = 2x 3 = x

2x+3 = -11 2x = -11-3 2x = -14 x = -7

5x-3 = 11+12x 5x-12x = 11+3 -7x = 14 x = -2

-x + 5y = 10 5y= 11 y = 11/5

11 So: x = 37

22

7

3x+5=7x-11 5=4x-11 4x=16 x=4

its 10

12 + 10 + 11 equals 33