depends what 'a' =
-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2
b = 2a + 11a + b = 5 which is b = 5 - atherefore2a + 11 = 5 - a (which is b = b)2a + a = - 11 + 53a = - 6a = - 2looking at first equation substitute - 2 for a:b = 2a + 11b = 2*(- 2) + 11b = - 4 +11b = 7to check:a + b = 5- 2 + 7 = 5
a + a + a - 2a = 3a - 2a = a
2a+5a+9a = 16a
depends what 'a' =
-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2
If: 2a+13 = 5a+1 Then: a = 4
b = 2a + 11a + b = 5 which is b = 5 - atherefore2a + 11 = 5 - a (which is b = b)2a + a = - 11 + 53a = - 6a = - 2looking at first equation substitute - 2 for a:b = 2a + 11b = 2*(- 2) + 11b = - 4 +11b = 7to check:a + b = 5- 2 + 7 = 5
a+a=1 2a=1 a=1/2
a + a + a - 2a = 3a - 2a = a
5a-20+2a = 6a-11 5a+2a-6a = 20-11 1a = 9 a = 9
Solve the following equation for A : 2A/3 = 8 + 4A
the answer
yes, if a=42a+3=112x4=88+3=11
a = 3a + 4 0 = 2a + 4 2a = -4 a = -2
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60