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2j+1/j+5 = 1

Multiply all terms by j+5 to eliminate the fraction:

2j+1 = j+5

2j-j = 5-1

j = 4

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Q: How do you solve 2j plus 1 divided by j plus 5 equals 1?
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How do you solve 3j - 13 equals 11 plus 2j?

3j-13=11+2j 3j-13-2j = 11+2j-2 j-13 = 11 j-13 +13 = 11 + 13 = 24 so j = 24


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It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.


What does j equal in 4j-24-6j120?

J does not equal a value since you didn't provide an equation; there's no equal sign nor a "right side." You have provided an expression that can be simplified but nothing more. Unfortunately, both equation and expression begin with the letter E in English which, I believe, can lead to the confusion. Now if 4j-24-6j equals 120 then we have something to work with! So then -24-2j equals 120 and -2j equals 144 and, finally, j equals -72. I hope this helps.


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The magnitude of (i + 2j) is sqrt(5). The magnitude of your new vector is 2. If both vectors are in the same direction, then each component of one vector is in the same ratio to the corresponding component of the other one. The components of the known vector are 1 and 2, and its magnitude is sqrt(5). The magnitude of the new one is 2/sqrt(5) times the magnitude of the old one. So its x-component is 2/sqrt(5) times i, and its y-component is 2/sqrt(5) times 2j. The new vector is [ (2/sqrt(5))i + (4/sqrt(5))j ]. Since the components of both vectors are proportional, they're in the same direction.


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Consider prime numbers p1, p2 greater than 2. Since p1 and p2 are prime and greater than 2, they are both necessarily odd. Hence, they are of the form: p1 = 2k+1, p2 = 2j+1, where j and k are positive integers. Their sum is then: p1+p2 = (2k+1)+(2j+1) = 2k+2j+2 = 2 (k+j+1). So 2 divides their sum, hence the sum can't be prime

Related questions

How do you solve 3j - 13 equals 11 plus 2j?

3j-13=11+2j 3j-13-2j = 11+2j-2 j-13 = 11 j-13 +13 = 11 + 13 = 24 so j = 24


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Suppose x equals 5 is a solution to the equation 4zx plus 1 equals j where z and j are constants. Find a solution to the equation 8zx plus 5 equals 2j plus 3?

It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.


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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals".


What does j equal in 4j-24-6j120?

J does not equal a value since you didn't provide an equation; there's no equal sign nor a "right side." You have provided an expression that can be simplified but nothing more. Unfortunately, both equation and expression begin with the letter E in English which, I believe, can lead to the confusion. Now if 4j-24-6j equals 120 then we have something to work with! So then -24-2j equals 120 and -2j equals 144 and, finally, j equals -72. I hope this helps.


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