3j + j = 4j
Add the vectors by components. That is, add the "i" components, and separately add the "j" components.
It is (3j)^6.
zero
15/16
3j-13=11+2j 3j-13-2j = 11+2j-2 j-13 = 11 j-13 +13 = 11 + 13 = 24 so j = 24
36.64
3i+2j)*(2i-3j)=0 bcz dot product is zero.
3j + j = 4j
2j+1/j+5 = 1 Multiply all terms by j+5 to eliminate the fraction: 2j+1 = j+5 2j-j = 5-1 j = 4
A = 3J; A - 5 = 5(j -5) Substitute for A: 3J - 5 = 5J - 25 Subtract 3J from each side: -5 = 2J - 25 Add 5 to each side: 0 = 2J - 20 Add 20 to each side 20 = 2J Divide each side by 2: J = 10 so Alison is now 30. (5 yrs ago they were 25 & 5)
3-2j.
the S I unit of inductance can be written as
Julia is 3. Kate is 10. Algebra: J + (2J +4) = 13 3J +4 = 13 3J = 9 J = 3
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Without information about j, the only possible answer is 3j + 15
Let S = Pair of Scissors J = Jar of Paste and P = Pencils Then 1S + 2J = 8P 1J = 1S + 1P From the second equation, 1S = 1J - 1P Substitute this value in the first equation: 1J - 1P + 2J = 8P so that 3J - 1P = 8P or 3J = 9P J = 3P Three pencils will balance 1 jar.