To me, this looks solved but of you want it in parametrics,
y = -3 +2t (teR)
3
2x-3=9 so 2x=12 and x=6
2x+3 = 7 2x = 7-3 2x = 4 x = 2
2x+3 = -11 2x = -11-3 2x = -14 x = -7
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
2x+3=9x 3=9x-2x 3=7x x=3/7
3x+4 = 2x-3 3x-2x = -3-4 x = -7
4x2 - 2x - 3 = 0 (2x + 1)(2x - 3) = 0 x = -(1/2) or (3/2)
2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x
2x + 3 = x 2x + 3 - 3 = x - 3 2x = x - 3 2x - x = x - 3 - x x = -3
3x-2 = 2x+3 3x-2x = 3+2 x = 5
2x - 4 = -10 2x = -10 +4 2x = -6 x = -3