These are known as simultaneous equations. To solve them you must change (if needed) one or both of the equations so that they can be combined in a way which eliminates one of the variables. See below:
1. 2x + y = 2
2. x + y = 1
There is little work to be done for this question. In both equations we have the variable y (and it is a single instance of positive y in each). Therefore, if we subtract one of equations from the other then y will disappear as y - y = 0.
So, subtracting 2. from 1.
[to do this just subtract each term in 2. from the corresponding term in 1. i.e. 2x - x, y - y and 2 -1]
gives:
3. x = 1 (often it is not quite as straightforward as getting the solution in one step, but we shan't complain!)
Now that we have a value for x, we just need to substitute this value back into one of the original equations and we will be able to solve for y.
So substituting x = 1 into 1. gives:
(2*1) + y = 2
2 + y = 2
y = 2 - 2
y = 0.
Therefore the solution is x = 1 and y = 0.
2x+a=p 2x=p-a x=.5p-.5a
many solutions
2x + 2x + 146 + 26 = 172 4x + 172 = 172 4x = 0 x = 0
2x+3 = 7 2x = 7-3 2x = 4 x = 2
(2x)ysquared
2x+a=p 2x=p-a x=.5p-.5a
y= -2x
3
8
many solutions
x=35
(3,3)
2x + 2x + 146 + 26 = 172 4x + 172 = 172 4x = 0 x = 0
2x+32 = 1 2x = 1-32 2x = -31 x = -15.5
2x+3 = 7 2x = 7-3 2x = 4 x = 2
If: x+1+2x = 1x+5 Then: x = 2
(2x)ysquared