Q: How do you solve 2x to the second power equals 228 by square root?

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13

If T2 = 78, then T = 78(1/2) or the square root of 78, or about 8.83.

-38

E is energy and MC2 is matter used to the second power... now you solve it

5 ^x = 0 5 = root square 0 5=0

-2y square exp power -2x-1

H= v over pie r to the second

if p² = 169, then p = ±√169 In other words, take the square root of 169 and p is either the positive or negative value of the square root.

If x equals the square root of ...., then you already have solved for x

It depends on which variable you wish to solve for.

8

87

30

PLUS 2

it is 1000 taking away 200 4 times

first square the first term then multiply the first and second term and multiply by 2 finally square the second term

x = +13x = - 13

68

36

88

34 = 81 so x is 4

You square the number in the parentheses.

Depends on the voltage. R equals V2/P . Or the current: R equals P/I2 .

Square root both sides and then x = 4

Take the square root of both sides. x=the square root of 10. It is an irrational number. Approximately 3.15