30a2 + a = 20
∴ 30a2 + a - 20 = 0
To factor this out, find two values whose sum is equal to the coefficient of the middle term, and whose product is equal to the product of the first and last terms' coefficients:
x + y = 1
xy = 600
Because x and y are so close together, we know that they'll be fairly close to the square root of 600, which is about 24.4949. So let's try 24 and 25:
24 × 25 = 600
bingo. So we'll take those two terms, and use them in our original equation, replacing the middle term with each of them (keeping in mind that their sum must equal the middle term):
∴ 30a2 -24a + 25a - 20 = 0
∴ 6a(5a - 4) + 5(5a - 4) = 0
∴ (6a + 5)(5a - 4) = 0
∴ a ∈ {-5/6, 4/5}
(20 - x)/5
20
To solve for x, we'd have to know what this expression equals.
y=16 x= -4
-7m + 20 = -17m - 1010m = -30m = -3
68
20 = 400
-3x + 5 = 20 -3x = 15 x = -5
Better formatting is cos(2x+20)=-0.5
balance the equation 3x-x=20-6 3x-x=2x 20-6=14 2x=14 x=7
3x^2=-20 so x^2=-20/3 this has no real roots but the plus of minus i(square root of 20/3) is a solution if we allow complex numbers.
20 plus 20 equals 4020 plus 20 = 40