30a2 + a = 20
∴ 30a2 + a - 20 = 0
To factor this out, find two values whose sum is equal to the coefficient of the middle term, and whose product is equal to the product of the first and last terms' coefficients:
x + y = 1
xy = 600
Because x and y are so close together, we know that they'll be fairly close to the square root of 600, which is about 24.4949. So let's try 24 and 25:
24 × 25 = 600
bingo. So we'll take those two terms, and use them in our original equation, replacing the middle term with each of them (keeping in mind that their sum must equal the middle term):
∴ 30a2 -24a + 25a - 20 = 0
∴ 6a(5a - 4) + 5(5a - 4) = 0
∴ (6a + 5)(5a - 4) = 0
∴ a ∈ {-5/6, 4/5}
(20 - x)/5
20
To solve for x, we'd have to know what this expression equals.
y=16 x= -4
-7m + 20 = -17m - 1010m = -30m = -3
68
-3x + 5 = 20 -3x = 15 x = -5
Better formatting is cos(2x+20)=-0.5
20 = 400
balance the equation 3x-x=20-6 3x-x=2x 20-6=14 2x=14 x=7
3x^2=-20 so x^2=-20/3 this has no real roots but the plus of minus i(square root of 20/3) is a solution if we allow complex numbers.
To solve the equation 8 plus what equals 20, we need to find the missing addend. We can do this by subtracting 8 from 20, which equals 12. Therefore, 8 plus 12 equals 20.