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How do you solve 4 is greater than or equal to 5 y over -2 keeping in mind that only the y is over the negative?
Wiki User
∙ 11y ago
To solve 4 ≥ 5y/-2 assuming normal algebraic rules regarding numbers and letters that are next to each other meaning multiply (and not as in a mixed number fraction):
4 ≥ 5y/-2 → 4 ≥ 5y/-2 (multiplying a fraction by a whole number → multiply numerator by the number)
→ 4 ≥ -5y/2 (make the denominator positive, so negate the numerator)
→ 8 ≥ -5y (multiply both sides by 2)*
→ 5y ≥ -8 (take the -5y and the 8 to the opposite sides, changing their signs)
→ y ≥ -8/5 (divide both sides by 5)
Thus any value of y greater than or equal to -8/5 = -13/5 is a solution.
* Multiplying (or dividing) both sides of an inequality by a negative number changes the direction of the inequality: greater than becomes less than and vice verse. By ensuring that the top of the negative "fraction" is the negative number and the bottom is positive, this change of inequality does not need to be remembered as a negative number is not used to multiply both sides.
Wiki User
∙ 11y ago
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This isn't an inequality, since there is no less-than, greater-than, less-than-or-equal, or greater-than-or-equal sign. However, solving inequalities is similar to solving equations; however, when you multiply by a negative number, you must change the direction of the inequality sign.
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How do you solve an inequality with fractions and variables on both sides?
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What is the difference between inpuality and equation?
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