Q: How do you solve 4y plus x equals 8?

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x = 4 and y = 0

You cannot solve one equation in two unknowns.

-x + 4y = 8

6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2

x = 4y - 2x = 6y + 84y - 2 = 6y + 8Subtract 4y from each side:-2 = 2y + 8Subtract 8 from each side:-10 = 2yDivide each side by 2:-5 = yx = 4y - 2x = -22

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x = 4 and y = 0

You can't solve it. But you can simplify it to get: 4x+y=2

You cannot solve one equation in two unknowns.

-x + 4y = 8

(4, 8)

6x = 32 - 4y and 4y - 8 = 6x so 32 - 4y = 4y - 8 ie 40 = 8y so y = 5 and x = 2

(9,7) by Kayla hamilton

x = 4y - 2x = 6y + 84y - 2 = 6y + 8Subtract 4y from each side:-2 = 2y + 8Subtract 8 from each side:-10 = 2yDivide each side by 2:-5 = yx = 4y - 2x = -22

-8 - 5y = 12 - 9y -8 + 4y = 12 4y = 20 y = 20/4 or 5

By definition: 4y-2 = 6y+8 4y-6y = 8+2 -2y = 10 y = -5 and by substituting this value into the equation x = -22

4x - 4y + 7 = 15to get it into y-intercept form do this...4x -4x - 4y + 7 - 7 = 15 - 7 - 4x-4y = 8 - 4x-4y / -4 = (8 / -4) + (-4x / -4)y = x + 2you did not give any values to plug in so this is as best an answer i can give

2x+4y = -8 4y = -2x-8 y = -1/2x-2 or y = -0.5x-2