0
This will equal -i. If you think about complex numbers graphically, it helps:
- i0 = +1, which points to the right
- i1 = +i, which points up.
- i2 = -1, which points to the left.
- i3 = -i, which points down.
- i4 = +1, and it repeats in fours.
So 32 is a multiple of 4, i32 will be the same as i4. So 31 is one less than 32, and i31 will be the same as i3, which is -i.
What else can I help you with?
How do you solve exponents?
You sole exponents by multiplying the hole number by the exponent.
Solve 7-24i complex number?
31
How do you solve a exponent?
Exponent is repeated multiplication
How do you solve a positive number with a negative exponent?
turn the positive number into its recipricol and the put the number of the negative number on the top
What is biased exponent?
A biased exponent is an exponent that is, in layman's terms, set aside when being used in high valued numbers, and basically just stored until the value of the number in the biased exponent needs to be used to solve an equation.
How do you solve a power?
To solve a power, you raise a base number to an exponent by multiplying the base by itself as many times as indicated by the exponent. For example, (a^n) means you multiply (a) by itself (n) times. If the exponent is zero, the value is 1, and if the exponent is negative, you take the reciprocal of the base raised to the positive exponent. Using these rules, you can simplify and calculate the value of powers efficiently.
Solved examples of bi complex numbers?
See the related link Answers dot com video for some examples of how to solve.
How do you solve a problem that has a variable with an exponent?
multiply
Do you see a relationship between the exponents of the base and the exponent of the product?
The exponent of the base is a step to solve the problems now the exponent of the product will also adjust a step to solve the equation but it contains more cooperative need.
How do you write a decimal using a negative exponent?
When you have a negative exponent (for example 3^-3) you could make the recipricol of the number. So, this would be 1/3^3. Then all that you would have to do is solve for the exponent ( so in this case the answer would be 1/27)
How can complex fractions be used to solve problems involving ratios?
The ratio of two quantities need not itself be a rational number - it can be a complex number.
What is the complex problem that you helped solve?
A complex problem I helped solve was when my friend was arguing with a girl .
