When you have the equation y-k=a(x-h)^2. You know the vertex=(h,k) And the axis of symmetry goes through the vertex; so h=the axis of symmetry. Say you have the axis is x=5. Thus h=5. Now all you have to do is plug in the two points in the eqaution and use a solution (try substitution) to solve for a. Then plug it back in to get k.
EX: x=5 (6,1) and (7,4)
1-k=a(6-5)^2 and 4-k=a(7-5)^2
1-k=a 4-k=4a
1-a=k *now substitute* 4-(1-a)=4a
4-1+a=4a
3=3a
a=1 (go back and plug in a)
k=1-1
k=0
The answer is: y=(x-5)
The given quadratic function can be rewritten in standard form as ( y = 2(x - 3)^2 + 5 ). The axis of symmetry for a quadratic function in the form ( y = a(x - h)^2 + k ) is given by the line ( x = h ). Here, ( h = 3 ), so the axis of symmetry is ( x = 3 ).
The formula to find the axis of symmetry for a quadratic function in the form (y = ax^2 + bx + c) is given by (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. The axis of symmetry passes through the vertex of the parabola and is crucial for graphing the function.
To fit a quadratic function to the points (-1, -11), (0, -3), and (3, -27), you can use the general form of a quadratic equation ( y = ax^2 + bx + c ). By substituting each point into the equation, you will create a system of three equations with three unknowns (a, b, and c). Solving this system will yield the coefficients that define the quadratic function that passes through the given points. In this case, the resulting quadratic function is ( y = -4x^2 - 4x - 3 ).
Yes, the formula for the area of a square, given by ( A = s^2 ) (where ( s ) is the length of a side), represents a quadratic function. The relationship between the area and the side length is quadratic because the highest exponent of the variable ( s ) is 2. This means that as the side length increases, the area increases at an increasing rate, characteristic of a quadratic function.
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
The given quadratic function can be rewritten in standard form as ( y = 2(x - 3)^2 + 5 ). The axis of symmetry for a quadratic function in the form ( y = a(x - h)^2 + k ) is given by the line ( x = h ). Here, ( h = 3 ), so the axis of symmetry is ( x = 3 ).
A parabola
The formula to find the axis of symmetry for a quadratic function in the form (y = ax^2 + bx + c) is given by (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. The axis of symmetry passes through the vertex of the parabola and is crucial for graphing the function.
To fit a quadratic function to the points (-1, -11), (0, -3), and (3, -27), you can use the general form of a quadratic equation ( y = ax^2 + bx + c ). By substituting each point into the equation, you will create a system of three equations with three unknowns (a, b, and c). Solving this system will yield the coefficients that define the quadratic function that passes through the given points. In this case, the resulting quadratic function is ( y = -4x^2 - 4x - 3 ).
by synthetic division and quadratic equation
vertex
Yes, the formula for the area of a square, given by ( A = s^2 ) (where ( s ) is the length of a side), represents a quadratic function. The relationship between the area and the side length is quadratic because the highest exponent of the variable ( s ) is 2. This means that as the side length increases, the area increases at an increasing rate, characteristic of a quadratic function.
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
i may only be 10 yrs old but i can say that an equation is not an function like the graphs of quadratic functions you will only be given an equation
Well, if the given quadratic equation cannot be factored, nor completed by the square, try using the quadratic formula.
only spheres take up all the given points in a given space
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