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How do you solve a quadratic function when given the axis of symmetry and two points?
Wiki User
∙ 13y ago
When you have the equation y-k=a(x-h)^2. You know the vertex=(h,k) And the axis of symmetry goes through the vertex; so h=the axis of symmetry. Say you have the axis is x=5. Thus h=5. Now all you have to do is plug in the two points in the eqaution and use a solution (try substitution) to solve for a. Then plug it back in to get k.
EX: x=5 (6,1) and (7,4)
1-k=a(6-5)^2 and 4-k=a(7-5)^2
1-k=a 4-k=4a
1-a=k *now substitute* 4-(1-a)=4a
4-1+a=4a
3=3a
a=1 (go back and plug in a)
k=1-1
k=0
The answer is: y=(x-5)
Wiki User
∙ 13y ago
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