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by synthetic division and quadratic equation
What else can I help you with?
How can you use a graph to find zeros of a quadratic function?
The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.
How do you find all the zeros of a function?
You could try setting the function equal to zero, and finding all the solutions of the equation. Just a suggestion.
What is next number is series 298 209 129 58 - 4?
The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.The answer can be any number that you like: it is always possible to find a polynomial of order 5 to fit the given numbers and any other number.The lowest degree polynomial that will fit the given numbers is the quadraticUn = (9n2 - 205n + 792)/2 for n = 1, 2, 3, .. . and that gives the next number as -57.
What is linear in 4x2 3x - 6?
4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors. Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function. 4x2 + 3x - 6 = 0 x2 + (3/4)x = 6/4 x2 + (3/4)x + (3/8)2 = 6/4 + 9/64 (x + 3/8)2 = 105/64 x + 3/8 = ± √(105/64) x = (-3 ± √105)/8 x = -(3 - √105)/8 or x = -(3 + √105)/8 Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].
How do you find a 4th degree polynomial with zeros x equals 4 x equals -3 and x equals 6i?
There are only three roots given so, in general, there is no unique answer. However, if it is a real polynomial, then its complex roots must come in conjugate pairs. Then 6i is a root implies that -6i is a root. So the polynomial is (x - 4)(x + 3)(x + 6i)(x - 6i) = (x2 - x - 12)(x2 + 36) = x4 + 36x2 - x3 - 36x - 12x2 - 432 = x4 - x3 + 24x2 - 36x - 432
How do you find polynomial whose zeros are given?
when the equation is equal to zero. . .:)
In given figure graph of polynomial x is given find the zero of polynomial?
To find the zeros of the polynomial from the given graph, identify the points where the graph intersects the x-axis. These intersection points represent the values of x for which the polynomial equals zero. If the graph crosses the x-axis at specific points, those x-values are the zeros of the polynomial. If the graph merely touches the x-axis without crossing, those points indicate repeated zeros.
what are all of the zeros of this polynomial function f(a)=a^4-81?
Find All Possible Roots/Zeros Using the Rational Roots Test f(x)=x^4-81 ... If a polynomial function has integer coefficients, then every rational zero will ...
How do you find the zeros of cubic polynomial equation?
If the cubic polynomial you are given does not have an obvious factorization, then you must use synthetic division. I'm sure wikipedia can tell you all about that.
State whether the following is a polynomial function give the zero s of the function if the exist f x x 2-6x plus 8?
The function ( f(x) = x^2 - 6x + 8 ) is a polynomial function because it is a quadratic expression. To find the zeros, we can factor it as ( (x - 2)(x - 4) ), which gives us the zeros ( x = 2 ) and ( x = 4 ). Thus, the zeros of the function are 2 and 4.
What are the zeros of the polynomial function f(x)x3-2x2-8x?
To find the zeros of the polynomial function ( f(x) = x^3 - 2x^2 - 8x ), we first factor the expression. We can factor out ( x ) from the polynomial, giving us ( f(x) = x(x^2 - 2x - 8) ). Next, we can factor the quadratic ( x^2 - 2x - 8 ) into ( (x - 4)(x + 2) ), leading to ( f(x) = x(x - 4)(x + 2) ). Therefore, the zeros of the function are ( x = 0 ), ( x = 4 ), and ( x = -2 ).
What is the remainder thereom?
The remainder theorem states that if you divide a polynomial function by one of it's linier factors it's degree will be decreased by one. This theorem is often used to find the imaginary zeros of polynomial functions by reducing them to quadratics at which point they can be solved by using the quadratic formula.
How do you find zeros of a polynomial?
If there is one variable. Then put each variable equal to zero and then solve for the other variable.
How can you use the zeros of a function to find the maximum or minimum value of the function?
You cannot. The function f(x) = x2 + 1 has no real zeros. But it does have a minimum.
How do you figure out how many real zeros a problem has?
To find the number of real zeros of a function, you can use the Intermediate Value Theorem and graphing techniques to approximate the number of times the function crosses the x-axis. Additionally, you can apply Descartes' Rule of Signs or the Rational Root Theorem to analyze the possible real zeros based on the coefficients of the polynomial function.
How Find a polynomial degree of 3 whose zeros are -2 -1 and 5?
Multiply x3 - 2x2 - 13x - 10
How do you find the y intercepts for a polynomial function?
To find the y-intercepts of a polynomial function, set the value of ( x ) to 0 and solve for ( y ). This involves substituting 0 into the polynomial equation and simplifying to find the corresponding ( y )-value. The y-intercept is the point where the graph of the function crosses the y-axis, represented as the coordinate (0, ( y )).
