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6x - 12 ≥ 2x + 20

First, get the numbers without a variable (x) together. You can do this by adding 12.

6x ≥ 2x + 32

Now, get the variables on the other side. You can do this by subtracting 2x.

4x ≥ 32

Now, you want to get x alone, so divide by the coefficient (4).

x ≥ 8

To graph this, graph the equation x = 8 (this will be a vertical line) and shade the area to the right of the line (where the numbers are larger than the number 8 (greater than)). Since x is also equal to eight, make certain the dots you used to graph the line are filled in. If it had not been equal to 8, you would leave these dots hollow.

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13y ago
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Q: How do you solve and graph 6x-12 greater than or equal to 2x plus 20?
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