b = 14
12/3 = 4
-0.5
You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.
X = 12
b = 14
12/3 = 4
-0.5
You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.
To solve this, you should first write it as an equation (where 'x' is the unknown value):8x = 12Then you can solve for x:8x =12X = 12/8X=1.5
X = 12
If the equation is structured like this: (8/x)=(12/(x+2)) then x=4. If the equation is structured like this: (8/x)=(12/x)+2 then x=-2.
-12
12y = 132y = 132/12y = 11
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
Answer:12y=132y=132/12=11
the answer is-10 = 12 +xx= -10-12x=-22this is the answerx= -22