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Q: How do you solve for the variable b in 2a plus 2b equals c?

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a = 4

depends what 'a' =

a + a + a - 2a = 3a - 2a = a

Subtract 2a from each side: P - 2a = b ie b = P - 2a

If: 2a+13 = 5a+1 Then: a = 4

Solve the following equation for A : 2A/3 = 8 + 4A

2a + 9 = 4a - 19 9 + 19 = 4a - 2a 28 = 2a a = 14

the answer

It is, in fact, an identity - which is an equation which is true for all values of the variable.

-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2

1

2a+5a+9a = 16a

a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)

:a = .5(hb+c) :2a = hb+c :2a−c = hb :(2a−c)/h = b

a+a=1 2a=1 a=1/2

It is the expression 3 + 2a.

2. 2 plus 2 equals 4 and 2(2)= 4

3a x 2a =24

14!!

A equals 20.

(2a + 1)(4a2 - 2a + 1)

A=2

2ab - 3b2 - 3b + 2a does not have a solution, as it is not an equation.

2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60

a = 1

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