2a + 2b = c
subtract 2a from both sides
2a - 2a + 2b = c - 2a
2b = c - 2a
divide both sides by 2
(2/2)b = (c - 2a)/2
b = (c - 2a)/2
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2a + 9 = 4a - 19 9 + 19 = 4a - 2a 28 = 2a a = 14
Subtract 2a from each side: P - 2a = b ie b = P - 2a
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
:a = .5(hb+c) :2a = hb+c :2a−c = hb :(2a−c)/h = b
To solve this, isolate x. first, add 10 to both sides. this will leave you with 2a + 15 = a Then, subtract 2a from both sides. This will leave you with 15 = -a Therefore, -15 = a
a = 4
depends what 'a' =
-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2
2a + 9 = 4a - 19 9 + 19 = 4a - 2a 28 = 2a a = 14
If: 2a+13 = 5a+1 Then: a = 4
a + a + a - 2a = 3a - 2a = a
a+a=1 2a=1 a=1/2
Subtract 2a from each side: P - 2a = b ie b = P - 2a
96
Solve the following equation for A : 2A/3 = 8 + 4A
the answer
It is, in fact, an identity - which is an equation which is true for all values of the variable.