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How do you solve j to the two-thirds powers minus 9j to the two thirds power equals -20?
Wiki User
∙ 12y ago
29
Dejah Walter
Wiki User
∙ 12y agoJ2/3 - 9 J2/3 = -20
To clear away some of the fog temporarily, let's write 'Q' in place of J2/3 :
Q - 9Q = -20
Perform the subtraction on the left side:
-8Q = -20
Multiply each side of the equation by -1 :
8Q = 20
Divide each side by 8 :
Q = 20/8 = 10/4 = 2.5
Now we can put J2/3 back in place of 'Q' :
J2/3 = 2.5
Raise each side to the 3/2 power :
J (2/3)(3/2) = (2.5) 3/2
J = sqrt(2.53) = sqrt(15.625) = 3.9528(rounded)
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