Best Answer

-5x2 = -75

x2 = 25

x = ±sqrt( 25 )

x = ±___

Q: How do you solve negative 5x squared equals negative 75?

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(x-3)(x-2)

x = 25 / 3squared + 5

5x2=8x Divide with x on both sides5x= 8 Solve xx=8/5

f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).

5x/6 = -9/6Multiply both sides of the equation by 6:5x = -9Divide both sides by 5:x = -9/5

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(x-3)(x-2)

x = 25 / 3squared + 5

(5x - 11)(2x + 1) if the term in x is negative; (5x + 11)(2x - 1) if it's positive.

5x2=8x Divide with x on both sides5x= 8 Solve xx=8/5

2222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222

f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).

2x squared minus 5x minus 3 factored is (2x+1)(x-3).

5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5

5x/6 = -9/6Multiply both sides of the equation by 6:5x = -9Divide both sides by 5:x = -9/5

128

3x^2 + 5x - 8 = 0 + 8 + 8 3x^2 + 5x = 0 8x ^2 = 0

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