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Q: How do you solve or factor 5x squared plus 33x plus 18?

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33x

33x + 9 = 18 ----> 33x = 9 ----> x = 3/11

9x + 2 + 24x + c = 33x + 2 + c If = 0 then c = -33x - 2 if = 1 then c = -33x - 1 if = 4 then c = -33x + 2 in general, c = -33x -2 + n2 where n is any integer.

ya...the answer to this math problem is: 5,940

3x2 + 33x + 54 =3(x2 + 11x + 18) = 3(x + 9)(x + 2)

3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.

21x + 12x -2 = 0 33x -2 = 0 33x = 2 x = 2/33 x = 0.06

25x+1=33x+7 25x=33x+6 -8x=6 x=-8/6 x=-4/3

I'm assuming that your solving for X. 21x + 12x - 2 = 0 33x - 2 = 0 33x = 2 x = 2/33 x =.06

80

(12)(33x)(92-12x) (12)(33x)(92)-(12)(33x)(12x) 36432x-4752x2 if this restatement of the grouping in the original problem is correct.

6x2 + 64x - 12 = 10 ∴ 6x2 + 64x - 22 = 0 ∴ 3x2 + 32x - 11 = 0 ∴ 3x2 + 33x - x - 11 = 0 ∴ 3x(x + 11) - 1(x + 11) = 0 ∴ (3x - 1)(x + 11) = 0 ∴ x ∈ {1/3, -11}

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