Tell me the equations first.
You need as many equations as you have variables.
You can solve the system of equations with three variables using the substitute method, or using matrix operations.
If you don't learn to solve equations then guess and check is the only way to arrive at new information.
You would solve them in exactly the same way as you would solve linear equations with real coefficients. Whether you use substitution or elimination for pairs of equations, or matrix algebra for systems of equations depends on your requirements. But the methods remain the same.
In beta decay equations, e- refers to an electron (in beta-), and e+ refers to a positron (in beta+).Not asked, but answered for completeness, ve refers to the electron neutrino that accompanies the positron, and v-e refers to the electron antineutrino that accompanies the electron.
Alpha decay is the loss of 2 protons and 2 neutrons Beta-decay is the loss of a positron or electron Gamma decay is the loss of a photon The equation relates this loss to energy produced E=mc^2
The equation for the positive beta decay of 188Hg is: 80188Hg --> 79188Au + 10e where e indicates a positron or positive beta particle.
A positron is the antiparticle of the electron. We write the electron as e- as it is negatively charged. We write e+ or β+ for the positron. The latter symbol uses the Greek letter beta as positron emission is one of the two forms of the radioactive decay known as beta decay. Links can be found below.
There is technically no such thing as positron decay. It's a misnomer. The nuclear decay process wherein a positron is emitted from a decaying nucleus is called positron emission or beta plus decay. A link is provided below that question and its answer.
If you are talking about beta+ decay, then the emission of a positron is accompanied with the emission of an electron neutrino.
Beta with a decay of a positron (as opposed to the more common electron).
There are two ways 174Ir can decay, alpha and positive beta, so there are two different equations. The equation for the alpha decay of 174Ir is: 77174Ir --> 75170Re + 24He representing the alpha particle as a helium nucleus. The equation for the beta+ decay of 174Ir is: 77174Ir --> 76174Os + 10e + ve wher 10e represents a positive beta particle or positron.
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It loses mass.
Depends on what type of radioactive decay you are talking about. Beta decay (electron or positron) will have a charge, while alpha decay will not. Beta decay can either be positron decay or electron decay. Positron will result in the parent to have the same atomic mass but a different atomic number. The atomic number will be one less than that of the parent. Meaning one proton will decay into a neutron and a positron, which is a positively charged particle. Electron decay results in the parent gaining a proton while the atomic mass stays the same. A neutron decays into a proton and an electron and the electron is emitted with a negative charge. Alpha decay, however, results in the emission of a neutral helium particle. Gamma decay results in the same parent with no loss of charge or atomic number and gives off a high energy photon called a gamma particle.
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve