Assuming the sign of 3 is a minus:
Add 3 to each side: 5x = 15
Divide each side by 5: x = 3
QED
y = 12x + 5x - 7 Since '12x' and '5x' both have the same variable, you are able to combine them. To do this you just need to add 12 + 5 to get 17. After doing this you can rewrite the equation as y = 17x - 7. You can then solve this equation for different values by plugging in a number for 'x' or 'y' or graphing the equation.
65
That equation has no solution. There is no possible number that's equal to 18 more than itself.
(3)(2)(2)5x=60 12(5x)=60 12(5x)/12=60/12 5x=5 x=1
First, change 2x+6y=32 to x+3y=16. Then solve for x, which is x=-3y+16. Then substitute -3y+16 as x into 5x-2y=12 and solve for y. 5(-3y+16)-2y=12 -15y+80-2y=12 -17y+80=12 -17y=-68 y=4 Then substitute 4 as y in either equation to solve for x. 5x-2(4)=12 5x-8=12 5x=20 x=4 The answer is x=4 and y=4, or (4,4)
5x = 80
y = 12x + 5x - 7 Since '12x' and '5x' both have the same variable, you are able to combine them. To do this you just need to add 12 + 5 to get 17. After doing this you can rewrite the equation as y = 17x - 7. You can then solve this equation for different values by plugging in a number for 'x' or 'y' or graphing the equation.
65
That equation has no solution. There is no possible number that's equal to 18 more than itself.
You need another equation to make this a linear equation so you can solve for both variables. One equation with two variables is not enough to determine the correct answer.
(3)(2)(2)5x=60 12(5x)=60 12(5x)/12=60/12 5x=5 x=1
12
First, change 2x+6y=32 to x+3y=16. Then solve for x, which is x=-3y+16. Then substitute -3y+16 as x into 5x-2y=12 and solve for y. 5(-3y+16)-2y=12 -15y+80-2y=12 -17y+80=12 -17y=-68 y=4 Then substitute 4 as y in either equation to solve for x. 5x-2(4)=12 5x-8=12 5x=20 x=4 The answer is x=4 and y=4, or (4,4)
5x - 11 - 36 is a math equation. 5x - 11 -36 can be simplified to read 5x- 47. I suspect that there is an equals missing, ie the question was/should be: "Solve for x in 5x - 11 equals -36" 5x - 11 = -36 → 5x = -25 → x = -5
5x+y=-7 3x+y=15 8=D
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
It is a linear equation in the variable x. You can solve for x using algebra: -5x + 3 = -22 -5x = -25 -x = -5 x = 5