(3)(2)(2)5x=60 12(5x)=60 12(5x)/12=60/12 5x=5 x=1
60/x = 5 60 = 5x x = 12
9x = 60x = 60/9 = 6 2/3 (or 6.67)
15x = 60 The variable is x.
Doesn't have integer roots. Quadratic formula gives roots as 3.71 and -5.38.
(3)(2)(2)5x=60 12(5x)=60 12(5x)/12=60/12 5x=5 x=1
5x+4 = 60 Move 4 to other side of the equation changing it to -4 5x = 60-4 5x = 56 Divide both sides of the equation by 5 to find the value of x: x = 11.2
5x+10=60 5x=50 5/5=1 50/5=10 So the answer is 10
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.
12 x 5 = 60
60/x = 5 60 = 5x x = 12
9x = 60x = 60/9 = 6 2/3 (or 6.67)
15x = 60 The variable is x.
It looks like an incomplete equation.
"Wat" is the variable.
No. An equation must be equal to something, that's why its called an equation. 15x = 60 is an equation, in which case x equals 4
-5x + y = -12- 3x + 6y = -12Since both of expressions have a value of -12, their sum is - 24. This is true only whenx = 20/9 and y = -8/9.-5x + y = -12y = 5x - 12- 3x + 6y = -12-3x + 6(5x - 12) = -12-3x + 30x - 72 = -1227x = 60x = 60/27x = 20/9y = 5x - 12y = 5(20/9) - 12y = 100/9 - 12y = (100 - 108)/9y = -8/9