Use the quadratic formula:
x = [-b +&- SQRT (b2-4ac)]/2a
where a,b,c are coefficients of the quadratic equation in the form of ax2+bx+c. So in your example a=1, b=-5, c=5
x = [-(-5) + SQRT(52-4*1*5)]/2*1 & x = [-(-5) - SQRT(52-4*1*5)]/2*1
x = [5 + SQRT (5)] / 2 & x = [5 - SQRT(5)]/2
To solve an equation with three unknowns, x, y and z, you require 3 independent equations.
5x+y=-7 3x+y=15 8=D
That equation has no solution. There is no possible number that's equal to 18 more than itself.
You need another equation to make this a linear equation so you can solve for both variables. One equation with two variables is not enough to determine the correct answer.
you need to find the value of X first before you can solve this equation
f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).
It is a linear equation in the variable x. You can solve for x using algebra: -5x + 3 = -22 -5x = -25 -x = -5 x = 5
Then x = 6 Therefore; 5x + 3 = 33 First you have to solve the value of X: 8X + 5X + 2X +4X = 114; OR 19x = 114. When you divide both sides of the equation by 19 to solve for X, you find that X = 6. Ergo, 5X + 3 = 30 + 3 = 33; hence, 5X + 3 = 33.
You cannot solve 1 linear equation in 2 unknown variables. You need at least two independent equations.
Multiply the bottom equation by -1
5x = 80
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept