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Q: How do you solve the following quadratic equations with the India method A. x2-2x-13 equals 0 B. 4x2-4x plus 3 equals 0 C. x2 plus 12x-64 equals 0 D. 2x2-3x-5 equals 0?

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Two equations: a linear one in y and a quadratic in x.

It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.

How about finding the solutions of the quadratic equation: x^2-14x+49 = 0

x = y = 3

no only equations with x2 and lower powers can be considered quadratic. those with x3 cannot be considered quadratic, just as x2 cannot be considered linear

If "equations-" is intended to be "equations", the answer is y = -2. If the first equation is meant to start with -3x, the answer is y = 0.2

( x - 2)( x - 6) = 0 x = 2 or x = 6

{-1,-2}

How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.

The Quadratic Formula song: (my grade saver) To the tune of the jack in the box song X equals negative B plus or minus square root of B squared minus 4AC all over 2A :)

No. [ y = 4x2 ] is a quadratic equation.

an equation has an equals sign.

Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.

X= (3/5 , -2)

x = -1.2, y = -3

It is a quadratic equation that has 2 solutions

Quadratic - the degree is two.

x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5

No

There are two solutions and they are: x = -1 and y = 3

It is a quadratic equation and its solutions can be found by using the quadratic equation formula.

It is consistent because x = -13 and y = -45

It is a quadratic equation in X.

Linear.

Yes.