( x - 2)( x - 6) = 0
x = 2 or x = 6
Two equations: a linear one in y and a quadratic in x.
X= 1.567764363, -9.567764363
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
Two equations: a linear one in y and a quadratic in x.
9x^(2) = 10x + 2 Is a quadratic eq'n. Algebraically rearrange to usual quadratic form . 9x^(2) -10x - 2 = 0 Does NOT factor , so apply Quadratic eq'n
Using the quadratic equation formula: x = -5-/+ the square root of 7
X= 1.567764363, -9.567764363
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
no only equations with x2 and lower powers can be considered quadratic. those with x3 cannot be considered quadratic, just as x2 cannot be considered linear
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
Why are Quadratic equations, which are expressed in the form of ax2 + bx + c = 0, where a does not equal 0,
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
a=5: c=4
the answer
Quadratic - the degree is two.