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Use l'Hospital's rule: If a fraction becomes 0/0 at the limit (which this one does),

then the limit of the fraction is equal to the limit of

(derivative of the numerator) / (derivative of the denominator) .

In this case, that new fraction is sin(3x)/cos(3x) .

That's just tan(3x), which goes quietly and nicely to zero as x ---> 0 .

Can't say why l'Hospital's rule stuck with me all these years.

But when it works, like on this one, you can't beat it.

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Q: How do you solve the limit 1 minus cos3x divided by sin3x as approaches 0?
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