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Assuming the figure is a plane regular rectangle.

Then there are two sides of 20m and two sides of 9m .

We could then write 20 + 20 + 9 + 9 = 58m

However we can alter this to (2 x 20) + ( 2 x 9) = 40 + 18 = 58m

or we could say 2*(20 + 9) = 2(29) = 58m.

However, you only mention two sides. you must specify the shape of the figure, be it a triangle, rectangle, kite. Trapezium and Square are discounted because a trapezium may have difference lengths ( an asymmetric trapezium), and a square has has four sides all the same length.

Then again the polygon might be of irregular shape( four different lengths).

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You need to know what the shape is before you can even think about trying to calculate its perimeter.

Q: How do you solve the perimeter of 20m to 9m?

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A 20m by 9m what?

The perimeter is 12m

The answer is 20m

Perimeter = 20+20+4+4 = 48m

A square with an area of 400m has a side length of 20m. The perimeter of a square of four times the length of one of its sides. Four times 20m is 80m. Therefore, the perimeter is 80m.

If it's a rectangle, 48 m.

It can be simplified to: 9m-2n

9m wide by 8m deep.

If they are the dimensions of a rectangle then the perimeter is: 9+3+9+3 = 24m

the p/a ratio is the sum of the perimeter divided by the area therefore if perimeter is 20m and the area 25m2 the sum is 20/25=0.8

This may get complicated. Try and stay with us if you possibly can:11 - 9m = 2Subtract 11 from each side:- 9m = -9Divide each side by -9:m = 1

Perimeter of rectangle: 2*(20+15) = 70m