It is 9m^2 - 9 = (3m + 3)*(3m - 3).
18m^2 - 12m + 2 = 2(9m^2 - 6m + 1) you can apply the formula (a - b)^2 = (a^2 - 2ab + b^2) or if you don't remmember it, continue to work: = 2(9m^2 - 3m - 3m + 1) = 2[(9m^2 - 3m) - (3m - 1)] = 2[3m(3m - 1) - (3m - 1)] = 2[(3m - 1)(3m - 1)] = 2(3m - 1)^2
3 meters. 9m2/3m Divide both sides by 1m 9m/3 Simplify 3m
9m - 6m = 21 Combine like terms: 3m = 21 Divide both sides by 3: m = 7
It is not possible to answer the question. There are three measures, but they cannot form a 2D shape - a triangle. If they are the lengths of sides of a solid figure, there is no information as to what shape that figure is - a cuboid or a parallelepiped.
9m + 9m + 3m + 3m = 24m
This question as written can be taken two ways: 9m + 6n - 3m + 7n = 6m + 13n, or (9m + 6n) - (3m + 7n) = 9m + 6n - 3m - 7n = 6m - n
9m
3m^2 - 9m = 0 factor out 3m 3m(m - 3) = 0 m = 0 -------- or m = 3 --------
It is 9m^2 - 9 = (3m + 3)*(3m - 3).
18m^2 - 12m + 2 = 2(9m^2 - 6m + 1) you can apply the formula (a - b)^2 = (a^2 - 2ab + b^2) or if you don't remmember it, continue to work: = 2(9m^2 - 3m - 3m + 1) = 2[(9m^2 - 3m) - (3m - 1)] = 2[3m(3m - 1) - (3m - 1)] = 2[(3m - 1)(3m - 1)] = 2(3m - 1)^2
12m + 2n - 3m + 11n = 9m + 13n
6m + 20 = 9m - 4 24 = 3m m = 8
3 meters. 9m2/3m Divide both sides by 1m 9m/3 Simplify 3m
The GCF of 9m and 3 is 3. You are left with 3m and 1. These cannot be further reduced by common factors.
9m² or 9 square meters or 9 meters squared
he was born in a 30ft by 10ft (9m by 3m) house