How do you solve the quadratic equation 10v2 equals 11v-7?

Answer 1

10v2 = 11v - 7
10v2 - 11v = 11v - 11v - 7
10v2 - 11v + 7= -7 + 7
10v2 - 11v + 7 = 0

This is in the standard form. There are many different ways to solve this, and I will use the 'completing the square' method.

(10v2 - 11v + 7)/10 = 0/10
v2 - (11/10)v + 7/10 = 0
v2 - (11/10)v = -7/10
v2 - (11/10)v + 121/400 = -7/10 + 121/400
(v-(11/20))2 = (-280+121)/400
(v-(11/20))2 = -159/400
v-(11/20) = ±√(-159/400)
v = (11±√(-159))/20
v = (11±i√(159))/20

Both of the roots are imaginary and do not cross the x-axis