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The reason you use the Quadratic method is because certain equations can't be factored. So let's start by defining the Quadratic Formula.

x = [-b +- √b2 - 4ac]/2a

For this equation, there are no factors of 6 that when added will equal 6, so we need to use the Quadratic Formula. Now let's find a, b, and c. The equation x2 - 6x + 6 = 0 is in the Standard Form of ax2 + bx + c = 0, so we just need to compare.

a = 1, b = -6, and c = 6

Now that we have a, b, and c defined, fill in the Quadratic Formula

x = [-(-6) +- √(-6)2 - 4(1)(6)]/2(1)

x = [ 6 +- √36 - 24]/2

x = [ 6 +- √12]/2

x = [ 6 +- 2√3]/2

x = (6/2) +- [(2√3)/2]

x = 3 +- √3

So, you have two possible answers: 3 + √3 and 3 - √3. Now you need to check each answer to make sure both are valid.

WARNING: It's hard to type complex fractions in Wiki Answers, so any clarification needed, let me know.

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Q: How do you solve the quadratic equation x2 minus 6x plus 6 equals 0?
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