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How do you solve the square root of t plus 12 minus t equals 0?
Wiki User
∙ 11y ago
I am going to guess that you mean:
Find t when
(√(t + 12)) - t = 0.
Then,
√(t + 12) = t;
t + 12 = t²; (squaring both sides)
t² - t - 12 = 0;
(t - 4)(t + 3) = 0; and
t = 4 or -3.
We'd best check both results, because we squared both sides at an earlier stage, which introduces an ambiguity and, probably, an extraneous answer:
Our original equation is seen to hold, for t = 4:
√(4 + 12)) - 4 = √16 - 4 = 4 - 4 = 0.
However, it does not hold, for t = -3.
√(-3 + 12)) + 3 = √9 + 3 = 3 + 3 = 6 ≠ 0.
Thus, the answer is that t = 4.
Wiki User
∙ 11y ago
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