If a question says solve the sum of the squares of 3 and 10, you would multiply 3 by 3 to get 9 and 10 by 10 to get 100, and add the two numbers to get 109.
32 + 102 = 9 + 100 = 109
To solve the sum and difference of two terms, you can use the identities for the sum and difference of squares. For two terms (a) and (b), the sum is expressed as (a + b) and the difference as (a - b). To find their product, you use the formula: ((a + b)(a - b) = a^2 - b^2). This allows you to calculate the difference of squares directly from the sum and difference of the terms.
There is a calculation error.
2 because 22+42 = 20
8081 can be the sum of two perfect squares because its perfect squares are 41 x41+80x80=1681+6400. Answer=1681+6400
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
The sum of their squares is 10.
If the regression sum of squares is the explained sum of squares. That is, the sum of squares generated by the regression line. Then you would want the regression sum of squares to be as big as possible since, then the regression line would explain the dispersion of the data well. Alternatively, use the R^2 ratio, which is the ratio of the explained sum of squares to the total sum of squares. (which ranges from 0 to 1) and hence a large number (0.9) would be preferred to (0.2).
If you have three cells in a row, column, or diagonal, and you know the sum of each, you can find the fourth.
There is a calculation error.
2 because 22+42 = 20
split 10 in two parts such that sum of their squares is 52. answer in full formula
8081 can be the sum of two perfect squares because its perfect squares are 41 x41+80x80=1681+6400. Answer=1681+6400
Sum of squares? Product?
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
There are several parallelogram depending on the context. One such is that the sum of the squares on the four sides of a parallelogram equals the sum of squares on its diagonals.
It is Fermat's theorem on the sum of two squares. An odd prime p can be expressed as a sum of two different squares if and only if p = 1 mod(4)
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