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Q: How do you solve this 15X2-24X12x2 28x?
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What is -28x-2?

In order to solve this equation you need to know what -28x-2 equals. If you were to assume it was 0 then x = 0.071 rounded


Solve the system 5x equals 2x plus 28x plus 10?

x=35


How do you solve 4x plus 28x-2?

4x + (28x -2) is not an equation. It doesn't ask a question, so it doesn't need answering or solving. The expression stands for a number. In order to know the number, you first have to know what number 'x' is.


What is x to the problem 68 plus 28x-28 equals 236?

68 + 28x - 28 = 236 28x + 68 - 68 -28 + 28 = 236 - 68 + 28 28x = 196 x = 7


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That depends on the - or + values of 28x and 980 which have not been given


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I assume that is (7x-2)^2 = 16 (7x-2)(7x-2) = 16 49x2 -28x +4 = 16 49x2-28x-12=0 use quadratic formula x = ( -b +/-sqrt(b2-4ac) ) /2a x = -2/7


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49x2+28x+4 = (7x+2)(7x+2) when factored


How do you factor -12x2 plus 28x -15?

what is -12X squared +28X - 15? i figured it out myself. its (-6X + 5)(2X - 3).


What is the gcf of 12x and 28x?

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What is 3x plus 25x?

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What was the total length of along distance phone call that cost 7.27 the rate was 55 cent for the first minute and 28 cent for each additional minute?

Suppose the total length was 1+x minutes.Then cost = 55 + 28x = 727So 28x = 272, therefore x= 24.So the call length was 25 minutes.Suppose the total length was 1+x minutes.Then cost = 55 + 28x = 727So 28x = 272, therefore x= 24.So the call length was 25 minutes.Suppose the total length was 1+x minutes.Then cost = 55 + 28x = 727So 28x = 272, therefore x= 24.So the call length was 25 minutes.Suppose the total length was 1+x minutes.Then cost = 55 + 28x = 727So 28x = 272, therefore x= 24.So the call length was 25 minutes.