You cannot solve a string of number, most of then separated only by spaces.
h = 63
The factors of 32 are: 1, 2, 4, 8, 16, 32 The factors of 63 are: 1, 3, 7, 9, 21, 63
95
23½ and 39½
63 multiplied by 32 is 2016.
32+16+8+4+2+1=63. 64 is deficient.
Break each number into its prime factors: 56 = 23 x 7 63 = 32 x 7 72 = 23 x 32 No prime factors are common to all three numbers, so we conclude that the GCF of the set is 1.
The GCF of 32 and 63 is 1.
63/32 is in its simplest form.
95
If you mean using numbers 2, 3 and 7 then one solution is :- 32 x 7 = 9 x 7 = 63
63 = 32*7