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How do you solve this simultaneous equation problem In 7 years Manuel will be twice as old as he was when Lupe was 9 years younger than he is now and Lupe will be one year older than he is now?
Wiki User
∙ 11y ago
Let x and y be Manuel's and Lupe's age now.
1. In 7 years Manuel will be twice as old as he (Manuel) was when Lupe was 9 years younger than he (assuming this he means "Manuel") is now
(x+7)=2(x-9)
x+7=2x-18
x=25
2. (In 7 years) Lupe will be one year older than he (Manuel) is now
y+7=x+1
y=x+1-7
y=25-6
=19
Therefore now Manuel is 25 and Lupe is 19.
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1. In 7 years Manuel will be twice as old as he (Manuel) was when Lupe was 9 years younger than he (assuming this he means "LUPE") is now
(x+7)=2(y-9)
x+7=2y-18
x=2y-25
(-->x=2x31-25=37)
2. (In 7 years) Lupe will be one year older than he (Manuel) is now
y+7=x+1
y=x+1-7
y=(2y-25)-6
y=31
Therefore now Manuel is 37 and Lupe is 31.
So it depends what it really means.
Not quite sure if i am right, please help improve the answer. Thanks:)
Wiki User
∙ 11y ago
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