In this case, the left part of the equation can easily be factored. If you are not familiar with factoring polynomials, use the quadratic formula.
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v2 + 6v + 8 = 0
(v + 4) (v + 2) = 0
v = -4
and
v = -2
v = -6
6x + 6v + 1 =6 (x + v) + 1
6v + 7 = -296v = -36v = -6
-v + 5 + 6v = 1 + 5v + 3Clean up and combine each side:(-v + 6v) + 5 = (1 + 3) + 5v5v + 5 = 4 + 5vSubtract 5v from each side:5 = 4.There is no solution.No value of 'v' can make [ 5 = 4 ].
The expression cannot be simplified.
v = -6
2u^2-6v-uv
It is: -10v+6v = -4v
6x + 6v + 1 =6 (x + v) + 1
6v + 7 = -296v = -36v = -6
No, the charger has to be equal to or greater than the device it is charging.
-v + 5 + 6v = 1 + 5v + 3Clean up and combine each side:(-v + 6v) + 5 = (1 + 3) + 5v5v + 5 = 4 + 5vSubtract 5v from each side:5 = 4.There is no solution.No value of 'v' can make [ 5 = 4 ].
When simplified: -27-8v
The expression cannot be simplified.
It is an equation and the value of v is -8
yes, you can.
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