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6v + 7 = -296v = -36v = -6
There is a formula for the "difference of squares." In this case, the answer is (6v + w)(6v - w)
6x + 6v + 1 =6 (x + v) + 1
6 volts.
v = -6
It is: -10v+6v = -4v
yes, you can.
6 and 18v, respectively.
2u^2-6v-uv
5(6v + 7)(6v - 7)
6v + 7 = -296v = -36v = -6
There is a formula for the "difference of squares." In this case, the answer is (6v + w)(6v - w)
The LCM of 18 and 6 is 18. The LCM of 18 and 6v is 18v.
6x + 6v + 1 =6 (x + v) + 1
The minimum speed of 6v motor to produce electricity is 15 Mph.
If the machine is designed to run on 6v and you use two 6v batteries instead of one, then . . . -- If you connect the two batteries in parallel, then they will last twice as long between recharges as one battery does. -- If you connect the batteries in series, then they will definitely overheat the motor, and possibly destroy it.
No, of course not. The 6v adapter only produces 6v, while the load expects 9v.