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6v + 7 = -296v = -36v = -6
There is a formula for the "difference of squares." In this case, the answer is (6v + w)(6v - w)
6x + 6v + 1 =6 (x + v) + 1
6 volts.
v = -6
The peak-to-peak (P-P) value of a 6V square wave is the difference between its maximum and minimum voltage levels. For a square wave that oscillates between +3V and -3V, the peak-to-peak voltage would be 6V (3V - (-3V) = 6V). If the square wave oscillates between 0V and 6V, the peak-to-peak voltage would also be 6V (6V - 0V = 6V). Therefore, regardless of the specific levels, a 6V square wave has a peak-to-peak voltage of 6V.
It is: -10v+6v = -4v
yes, you can.
6 and 18v, respectively.
2u^2-6v-uv
5(6v + 7)(6v - 7)
6v + 7 = -296v = -36v = -6
There is a formula for the "difference of squares." In this case, the answer is (6v + w)(6v - w)
The LCM of 18 and 6 is 18. The LCM of 18 and 6v is 18v.
6x + 6v + 1 =6 (x + v) + 1
The minimum speed of 6v motor to produce electricity is 15 Mph.
If the machine is designed to run on 6v and you use two 6v batteries instead of one, then . . . -- If you connect the two batteries in parallel, then they will last twice as long between recharges as one battery does. -- If you connect the batteries in series, then they will definitely overheat the motor, and possibly destroy it.