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5x-2y equals -3 what is the slope?
5x-2y=-3 -2y=-5x-3 y=(5/2)x+3/2 slope is 5/2
How do you solve systems of equations using substitution?
3(5x-2y)=18 5/2x-y=-1
Solve the following system of equations 5x plus y equals -9 -5x plus 2y equals 0?
x = -1.2, y = -3
What is the slope and y-intercept of 5x plus 2y plus 3 equals 0?
Put in point slope/function form. 5X + 2Y + 3 = 0 5X + 2Y = - 3 2Y = - 5X - 3 Y = - 5/2X - 3/2 slope = - 5/2 ---------------- Y intercept = - 3/2 -------------------------
How do you solve for 5x plus y equals 1 and 3x plus 2y equals 2?
For 5x+y=1, you would subtract 5x from each side, so you would get y=1-5x For 3x+2y=2, you would subtract 3x from each side, and then divide by 2. 2y=2-3x y=1-(3/2)x
Solve 5x 2y5 and 3x-4y-23 using elimination?
5x - 4y ≥ -203x - 2y ≤ -8y ≥ -3
5x-2y equals -3 what is the slope?
5x-2y=-3 -2y=-5x-3 y=(5/2)x+3/2 slope is 5/2
How do you solve systems of equations using substitution?
3(5x-2y)=18 5/2x-y=-1
Solve the following system of equations 5x plus y equals -9 -5x plus 2y equals 0?
x = -1.2, y = -3
What is the slope and y-intercept of 5x plus 2y plus 3 equals 0?
Put in point slope/function form. 5X + 2Y + 3 = 0 5X + 2Y = - 3 2Y = - 5X - 3 Y = - 5/2X - 3/2 slope = - 5/2 ---------------- Y intercept = - 3/2 -------------------------
How do you solve for 5x plus y equals 1 and 3x plus 2y equals 2?
For 5x+y=1, you would subtract 5x from each side, so you would get y=1-5x For 3x+2y=2, you would subtract 3x from each side, and then divide by 2. 2y=2-3x y=1-(3/2)x
Is 3(3x 2y) equivalent to 5x 5y?
No
5x plus 2y equals 19 x - 2y equals -1?
(3, 2)
3x plus 2y equals 20 and 5x-2y equals 1?
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
9 plus 2y 3 solve for y?
9+2y=3 2y=-6 y=-3
What is the solution to 2y equals 5x - 1 x equals y plus 2?
If those are two different equations, such that 2y=5x-1 and x=y+2, then you subsitute y+2 in for x in the first equation, and when you solve the whole thing, you get that x=-1 and y=-3, or the point (-1,-3)
What is the value of x and y in this equation 2x plus 3y equals -5 and 5x plus 2y equals 4 The number for x and y stay the same for both parts of the equation?
This is a system of equations, and we can use various methods to solve it. We'll use substitution in this case. We're told: 2x + 3y = -5 5x + 2y = 4 To solve by substitution, what we need to do is take either one of those equations, and solve it for either x or y. Let's take the second one and solve it for x: 5x + 2y = 4 5x = 4 - 2y x = (4 - 2y)/5 Now we can take that solution for x, and substitute it into the other equation: 2x + 3y = -5 2((4 - 2y)/5) + 3y = -5 (8 - 4y) / 5 + 3y = -5 (8 - 4y + 15y) / 5 = -5 8 - 4y + 15y = -25 11y = -33 y = -3 We now have a value for y, and can plug it into either of the original equations to solve for x: 2x + 3y = -5 2x + 3(-3) = -5 2x - 9 = -5 2x = 4 x = 2 To verify our answer, we can plug either x or y into the other of our original equations, and see if we get the same result for the other variable: 5x + 2y = 4 5(2) + 2y = 4 10 + 2y = 4 2y = -6 y = -3 So that confirms our answer, and the two equations intersect at the point (2, -3).
