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Q: How do you solve y equals -4x plus 3?

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x= -.5

-4x+3 = 23+6x -4x-6x = 23-3 -10x = 20 x = -2

4x+9 = 7x+3 4x-7x = 3-9 -3x = -6 x = 2

5+4x-7 = 4x+3-x 4x-2 = 3x+3 4x-3x = 3+2 x = 5

5x + 3 = 4xSubtract 3 from each side:5x = 4x - 3Subtract 4x from each side:x = -3

x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}

If you would to solve for (l) then l = 4x/2 + 3/2 (4x + 3 is over 2).To solve for x. x = 2l/4 + 3/4 ( 2l + 3 is over 4)Hope this helps.

4x + 3 = -3 + 2x + 14 2x + 3 = -3 +14 2x + 3 = 11 2x = 8 x=4

If: 20x+5y = 15 Then: y = -4x+3

8x+30=4x+18 -4x -4x 4x+30=18 -30 -30 4x=-12 4x/4=-12/4 x=-3

-4x + 8 = -4 -4x + 8 - 8 = -4 -8 -4x = -12 -4x/-4 = -12/-4 x = 3

4x - 3 - 5x + 7 = 6 4x - 5x = 3 - 7 + 6 -1x = 2 x = -2

7x = 3x - 12 4x=-12 x=-3

y = 4x-3

4x + 3y = 7 y = [(-4)/3] x + 7/3

-3

4x2 = -12x, divide both sides by 4x: x = -3

9x = 60x = 60/9 = 6 2/3 (or 6.67)

2x + 3 + 3x = x + 11 5x + 3 = x + 11 4x + 3 = 11 4x = 8 x = (8/4) x = 2

x=3

= 3

3+6x = 4x+9 6x-4x = 9-3 2x = 6 x = 3

6x + 14 = 20 + 4x ------ Combine like terms (subtract 4x and 14 from both sides). 2x = 6 --------------------- Divide by 2. x = 3

5x - 4x = 13 - 3 ie x = 10

7x = 20 + 4xSubtract 4x from each side of the equation:3x = 20Divide each side by 3 :x = 20/3