Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x
x2 +7x = 30 x2 +7x - 30 = 0 (x + 10)(x - 3) = 0 Now: x + 10 = 0 or x - 3 = 0 So: x = -10 or x = 3
x + 30 = 64 Therefore, x = 64 - 30 x = 34
4x+6x=30 is the same as: 10x=30 so we divide by 10 and get: x=3 (I do not see how this relates to calculus, but O.K.)
(1) 5x+y=-12 (2) 7x-3y=-30 From (1) one gets y = -12-5x Put into (2) 7x-3y = 7x -3 (-12-5x) = 7x + 36 +15 x = 22x +36=-30 22x = -30-36 = -66 so x = -3 and y=-12-5x = -12-5x-3= 3 The solution is (-3,3)
To solve the equation n + 3x6 = 30, first calculate 3x6, which equals 18. Then subtract 18 from both sides of the equation to isolate n. Thus, n = 30 - 18, which simplifies to n = 12.
(3,3)
It does not help you.
The sum of 18 + 30 is 48.
-6
18 + 10 + 20 + 30 + 15 + 50= 143
N+18=30. Subtract 18 both sides N=12
45 = 30 + m Subtract 30 from both sides: 15 = m
11a+9 = 4a+30 11a-4a = 30-9 7a = 21 Solution: a = 3
30
30 - 12 = 18
v is -15... -15*2 = -30... -30+11= -19.