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If the sum of the digits can be divided by 3. 93 is divisible by 3 because 9+3=12 we know 12 is divisible by 3 because 1+2=3 so the number is divisible by 3.

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Q: How do you tell if a number is divisible by 3?

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You can tell if the sum of the digits can be divided by 3.

If it's even and divisible by 3, it's divisible by 6.

If it's divisible by 3 and 4, it's divisible by 12.

No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.

No, it is not evenly divisible by 3. The answer you get is 6,665.3333. A trick to tell is a number is divisible by 3 is to add up the digits and see if they are divisible by 3. In this case, 34 is not divisible by 3.

If the number is divisible by 2 and 3, it can also be divided by 6.For example - 12126 is divisible by 2 and 3 and6Divide it by 6 and see if you get a whole number.

If the sum of the digits is a multiple of 3, the whole number is divisible by 3.

Yes, it is a composite number. It's divisible by 3. A quick way to tell if a number is divisible by 3 is to add up all the digits in the number. If their sum is divisible by 3, then the number is divisible by 3. For example, 4 + 2 + 3 = 9, and 9 is obviously divisible by 3. So, 423 must be divisible by 3. 423 divided by 3 is 141.

6, 9, 12, 30, 60, 90, 360, 690, 930, or (162,591). Here's a secret: If the sum of a number's digits is divisible by 3, then the number is divisible by 3. That's how you can tell quickly that 162,591 is divisible by 3.

Not evenly. An easy way to tell is that its digits add up to 7, a number which is not divisible by 3.

If the sum of its' digits are divisible by 3 for all numbers greater than 9.

Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.

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