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Yes, it is a composite number. It's divisible by 3. A quick way to tell if a number is divisible by 3 is to add up all the digits in the number. If their sum is divisible by 3, then the number is divisible by 3. For example, 4 + 2 + 3 = 9, and 9 is obviously divisible by 3. So, 423 must be divisible by 3. 423 divided by 3 is 141.

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Q: Is 423 a composite

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423 is a composite number. Its prime factorisation is 3 x 3 x 47.

423 is a composite number because it has more factors than one and itself. Its prime factorisation is 3 x 3 x 47.

compositefactors: 3 and 9

well first off all even numbers are composite (except 2). you can fist off tell if a number can be divided by three by adding up its digits such as 423. We know that 3 can go into this because the digits add up to 423. please take third grade again to learn the rest of the rueles

423% = 4.23 = 423/100 in fraction

423 percent as a decimal = 4.23 423% = 423%/100% = 4.23

423-298 = 125

x + 2x + 423 = 3x + 423

423 = 1*423, 3*141, 9*47

423 = 42,300%

The factors of 423 are: 1 3 9 47 141 423

423/3 = 141

423 = CDXXIII

423

Yes. 423 is divisible by 1, 3, 9, 47, 141, 423.

423 = CDXXIII

423 + 7 = 430

229 x100/423 = 54.14%

423 in roman numeral is CDXXIII

423x1 423

48,395 multiplied by 423 = 20,471,085

423 to the nearest tens is 420

It is: 155+268 = 423

6 + (23 424 243 423 423 243 244 224 242 424) = 23 424 243 423 423 243 244 224 242 430

There are 10 millimetres in one centimetre. Therefore, 423 millimetres is equal to 423/10 = 42.3 centimetres.