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A single number cannot be turned into a percent for a circle graph. You need a total.

If the number is N and the total is T then the percentage is 100*N/T

and then, for a circle graph, the relevant segment should subtend an angle of 360*N/T degrees (or 2*pi*N/T radians).

Q: How do you turn a number into a percent for a circle graph?

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Divide the degrees by 360 and multiply by 100. Or, simply divide the degrees by 3.6

Multiply the percentage by 360.For example, 32.5%*360 = .325*360 = 117 degrees.first divide the percent by 100. then Multiply by 360.

you turn percents into mixed numbers by turning the percent into a fraction then a mixed number

It depends on what graph but a quarter turn on a graph is the same as a 90 degrees turn.

To convert any number to a percent, multiply the number by 100. 66.66 = 6,666 percent.

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Divide the amount of degrees by 3.6 to change it to percent.

Divide the degrees by 360 and multiply by 100. Or, simply divide the degrees by 3.6

Multiply the percentage by 360.For example, 32.5%*360 = .325*360 = 117 degrees.first divide the percent by 100. then Multiply by 360.

once you have the percentage of a number you turn it into a decimal and multiply it by 360. for example. if your percent is 36% you make that .36 which is the decimal form of that percent as well as .59 is the decimal form for 59%. so next you multiply .36 by 360 360 x .36= 129.6 which is your degree.

To turn a number into a percent is multiply it by 100 and you get your percent.

you turn percents into mixed numbers by turning the percent into a fraction then a mixed number

It depends on what graph but a quarter turn on a graph is the same as a 90 degrees turn.

To convert any number to a percent, multiply the number by 100. 66.66 = 6,666 percent.

To get a percent into a decimal, divide by 100.

multiply by 100.

Although closely related problems in discrete geometry had been studied earlier, e.g. by Scott (1970) and Jamison (1984), the problem of determining the slope number of a graph was introduced byWade & Chu (1994), who showed that the slope number of an n-vertex complete graph Knis exactly n. A drawing with this slope number may be formed by placing the vertices of the graph on a regular polygon. As Keszegh, Pach & Pálvölgyi (2011) showed, every planar graph has a planar straight-line drawing in which the number of distinct slopes is a function of the degree of the graph. Their proof follows a construction of Malitz & Papakostas (1994) for bounding the angular resolution of planar graphs as a function of degree, by completing the graph to a maximal planar graph without increasing its degree by more than a constant factor, and applying the circle packing theorem to represent this augmented graph as a collection of tangent circles. If the degree of the initial graph is bounded, the ratio between the radii of adjacent circles in the packing will also be bounded, which in turn implies that using a quadtree to place each graph vertex on a point within its circle will produce slopes that are ratios of small integers. The number of distinct slopes produced by this construction is exponential in the degree of the graph.

Multiply the whole number to 100%.