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H_0:μ_1-μ_2=d assuming heterogeneity t=((x ̅_1-x ̅_2 )-(μ_1-μ_2 ))/√((s_1^2)/n_1 +(s_2^2)/n_2 ) Student t(υ)

ν=((s_1^2)/n_1 +(s_2^2)/n_2 )^2/[((s_1^2)/n_1 )^2/(n_1-1)+((s_2^2)/n_2 )^2/(n_2-1)]

H_0:μ_1-μ_2=d assuming homogeneity t=((x ̅_1-x ̅_2 )-(μ_1-μ_2 ))/(s_p √(1/n_1 +1/n_2 )) Student t(υ) ν=n_1+n_2-2

H_0:μ_d=0 t=(d ̅-μ_d)/(s_d⁄√n) Student t(υ) ν=n-1

H_0:p_1-p_2=0 z=((p ̂_1-p ̂_2 )-(p_1-p_2 ))/√((p ̅(1-p ̅))/n_1 +(p ̅(1-p ̅))/n_2 ) N(0,1) NA

H_0:σ_1^2=σ_2^2 F=(s_Larger^2)/(s_Smaller^2 ) F_(ν_1,ν_2 ) ν_i=n_i

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Q: How do you use Comparison of Means Proportions and Variance (Two population)?
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Homogeneity means that the statistical properties of the variable which is being studied remain the same across the population. Heterogeneity means that they do not: it could be that the mean changes between different subsets of the population or the variance does.


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