Not the best way of finding out if a triangle is right angled. But if you can find two if the sides which have gradients which when multiplied together gives -1, then the angle between them is a right-angle.
This comes from the fact that if the slope of a line is a/b, then the slope of a perpendicular line is -b/a and the product of (a/b)(-b/a)=-1.
If a triangle is an isosceles triangle as well as being a right-angled triangle, the size of the two angles (that are not right angles) are 45 degrees.
Pythagoras discovred it to find unknown sides in a right angled triangle
Congruent shapes simply means both shape are identical, therefore to find two right-angled triangles are congruent you:Use a tracing paper and trace the right-angled triangle (A) and see if it matches with the other right-angled triangle (B).Another way is to find the positions or measure the triangles, if the match then viola! they're the same.
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
The question is poorly specified, since the given triangle can be right angled at A or C. If it is right angled at A, then bc2 = ab2 + ac2 so that ab2 = 100 - 16 = 84 and ab = sqrt(84) = 9.165 Or it is right angled at C, and ab2 = bc2 + ca2 = 100 + 16 = 116 so that ab = sqrt(116) = 10.770
how to find the perimeter of a right angled triangle using the area
By definition, the hypotenuse is the side opposite the right angle in a right angled triangle. Therefore, a hypotenuse does not exist as one of the three sides in a non-right angled triangle.
If a triangle is an isosceles triangle as well as being a right-angled triangle, the size of the two angles (that are not right angles) are 45 degrees.
The area of a right-angled triangle with base 8 cm and hypotenuse 10 cm is: 24 cm2
sin, tan and cos can be defined as functions of an angle. But they are not functions of a triangle - whether it is a right angled triangle or not.
thePythagoras theorem was simply to calculate the sides of a right angled triangle, isosceles triangle and cubes and cuboids here is the formulas; right angled triangle= a^2+b^2=c^2 for an isosceles triangle, split it in half and you have two right angled triangles, use the formula above afterwords cube/cuboids, you can find the face diagonal and the space diagonal by using the formula above to calculate if it is a right angled triangle or not, then you need the 3 sides( a, b and c)add a^2 and b^2, then calculate c^2, if a^2+b^2 is equal to c^2, then it is a right angled triangle, if not, then it isn't a right angled triangle by the converse of Pythagoras, hope this helped :-) hope its not to complicated for you!
Pythagoras discovred it to find unknown sides in a right angled triangle
Congruent shapes simply means both shape are identical, therefore to find two right-angled triangles are congruent you:Use a tracing paper and trace the right-angled triangle (A) and see if it matches with the other right-angled triangle (B).Another way is to find the positions or measure the triangles, if the match then viola! they're the same.
Use the Pythagorean Theorem, a2 + b2 = c2
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
The question is poorly specified, since the given triangle can be right angled at A or C. If it is right angled at A, then bc2 = ab2 + ac2 so that ab2 = 100 - 16 = 84 and ab = sqrt(84) = 9.165 Or it is right angled at C, and ab2 = bc2 + ca2 = 100 + 16 = 116 so that ab = sqrt(116) = 10.770
a2 +b2 = c2 (c is the longest side/or hypotenuse)