It is: 5/5 to the power of 5 = 1 or 5 to the power of 5-5 = 1
55 of them.
5/5=1 Keep this for later. so 2 5s used. Then do 5*5=25, so 5 5s used as 25 has a five in it, now do 1 - 25=24.
In the Rb atom, the electron configuration is [Kr]5s^1. This means there is 1 electron in the 5s sublevel of the Rb atom.
well here is how i wud do it................ 5 x 5 - 1 = 24
To write four 5s and make them represent 56 you need to write 55 + 5/5. When worked out it becomes 55 + 1 (5/5=1) which equals 56.
That depends on the value of s.
there are 3 2/5ths in 1
5x7=35, then 3-1=2, so 35+2=37
1, remainder 1
The orbital diagram for silver (Ag) is [Kr] 4d^10 5s^1. This means that the electron configuration of silver is [Kr] 4d^10 5s^1, indicating that silver has a completely filled 4d orbital and one electron in the 5s orbital.
The last electron in silver is in the 5s orbital. Silver has an electron configuration of [Kr] 4d^10 5s^1, indicating that the last electron is in the 5s orbital before entering the 4d subshell.
1 - s = 6 - 6s => 5s = 5 so that s = 1